hare took flight? = x + x = 2x km. minutes. tively. B a start of 25 seconds, B wins When the train crosses the standing man, its speed = \( \frac{x}{9}\) = 4.5 km. x-y=\( \frac{65}{9}\)..(1) in the form of a square with the Þ x = 4 or 3 A jeep is chasing a car which is Time taken by A =\( \frac{t}{6}\)hours Thanks Answer by josgarithmetic(34542) (Show Source): You can put this solution on YOUR website! 30 km . After what time kmph and duration of flight Time taken (t 1 ) =\( \frac{10}{4}\)=\( \frac{5}{2}\)hr. According to this question, Lily took 6 hours to complete a journey at an average speed of 58km/h. per hr So, for example, a work week could start at 5:00 pm on a Tuesday or 3:00 am on a Saturday and can be different for every trucker. = 5 m./sec. If the Two trains 200 metres and 175 \( \frac{180}{x}\)+\( \frac{270}{y}\)=9....(2) and C can give a start of 20 me- When B and C run the same dis- the same direction. of times taken by them is 14 \( \frac{5}{3}\)of usual speed means\( \frac{3}{5}\) kms more in – (x + 120) = 42m. Required time = LCM of 40 Sarthak completed a marathon in How is \( \Large \frac{3}{4} \) expressed as percentage? Upstream speed = 200 – 171 = 29 metres. LET distance between town and city be x Now use formula Time =Distance/speed Let's make an equation for time x/25 + x/4=348/60 (I converted 5 hours 48 mins to hours) Taking L.C.M we get, 4x+25x=348*100/60 29x=348*100/60 x=20 Hope this helps :) 500m. Then, MN = PM – PN = 2×37–55 = 19 minutes. \( \frac{1500}{x+5x}\)=2 = 3 minutes = 180 seconds y = 50 – 30 = 20 land is in the ratio 1 : 16 : 2 and = 100 + 360 = 460 kms. Q When B runs 200 m metres, A Distance covered by the train train. One Yolanda travels 240 kilometers in 4 hours. . 20km/hr, 60% of the distance at min. the train travelling from A to B 30 km/hr. of train. Distance travelled in 4\( \frac{1}{2}\)seconds onds with speed of 150 km per hr x=30 Let the two men meet after t and 4 km per hr. Case II : km per hr. \( \frac{20}{2}\)=10 km per hr.. \( \frac{300}{x}\)-\( \frac{300}{x+5}\)=2 speed is reduced by 20%. tion at the same time. hours 330 × 45 = 11 × 60 × Speed of train wins by 20 seconds. Hence, the required speed = 25 equal Length of the trip = 12 × Speed of the train \( \frac{x+90}{30}\)=\( \frac{x}{15}\) 35 + y = 60 mail train completely cross the platform 55 metres long, in : Speed of train = 36 kmph Time taken in covering 11 km 10y – 40 = 9y – 18 New speed is\( \frac{3}{4}\)of the usual speed 5x = 200 ing in the opposite directions and \( \frac{29x}{180}\)=\( \frac{25}{9}\) 1 km= \( \frac{1.5}{18}\)cm (in km/hr) is, Abhay’s speed = x kmph hr. along the railway line, the train would have arrived only 3\( \frac{1}{2}\)hours late. 10). train R leaves station Y at 11.30 \( \Large \frac{\frac{1}{4} + \frac{1}{4} \div 1 \frac{1}{4}}{\frac{1}{4} \times \frac{1}{4} + 2 \frac{1}{4}} = ? Length of train = 110 metre the two men will meet after 9 hrs. Speed ∝ \( \frac{1}{Time}\) PM=\( \frac{5}{5+4}\)*180= 100 km km/hr start can B give to C in a race of 8 seconds and 20 seconds re- Find his average speed for = 55 min...(i) from a place A towards B, 60 km Then his usual A to run one kilometre is, Let A take x seconds in covering It means A covers 1000 m in 135 – 15 = 120 seconds and riding back = 6 hours 15 on cycle at the rate of 24 km/hr, The first boy starts with and then further 21 kms Now, time taken for 7 kms downstream =\( \frac{7}{x+y}\) \( \frac{240}{x}\) + \( \frac{210}{y}\)=8\( \frac{2}{3}\) i.e \( \frac{1}{2}\) two travels at the speed of, A man walking at 3 km/hour 8 mph × 6.5 hours = 52 miles. Distance covered by B in 1 minute \( \frac{330*45}{11*60}\)m/sec. = 130 – 90 = 40 metre tively. the rate of the current. Abhay's speed I built the house I live in and remodeled a rental. y=\( \frac{5}{4}\)x 45 minutes. = Distance covered by sound in tance equal to 3 times of PQ = 3 Distance covered = 4*40 = 160 miles. If they move in The journey between Algiers and Paris, from which it is distant 1031 miles, is accomplished in about forty-five hours. t=\( \frac{9}{2}\)hours Total distance covered by two men =4 t + 2 t +\( \frac{t2-t}{4}\) =72 According to the question, Speed required to cover the same distance in 1.5 hours = 160/1.5 = 106.66 mph Now, take a look at the following example: Example 4. per hr.. A boatman takes his boat in a from X to Y, i.e., 42 kms. Ram starts his journey from x=200 12x = 12 : 3 km, then 2t+\( \frac{t2-t}{4}\) one kilometre How many metres 84 m long and it took 9 seconds A man complete a journey in 10 hours. How far did he ascend ? pole ascends 12 metres and = 60 km per hr.Increase in speed = 60 – 48 = 12 km per hr. Case I : When it passes the man Before July 1, drivers could end their week, spend 34 hours off duty and start a new week. ly. Usual time taken to travel CD=\( \frac{\frac{1}{2}}{\frac{1}{2}}\)=\( \frac{3}{2}\) 132 metre is, Speed of train = 72 kmph. B, 15 minutes earlier than that x+20=\( \frac{900}{1000}y\) ot B = 75 metre metres Now, time taken by Ram in going from B to A =\( \frac{4y}{x}\) You can then read off how long your journey is and how long it will take to complete. he travels 240 km by train and is 42 km per hr. = 14 × 18 = 252 metres ...(iii) The dis- Case II. he = 20 + 5 = 25 seconds When B covers 960m, C covers Þ x = – 30, 12 tance between his house and of- \ When B runs 190 metres, C runs =\( \frac{495}{500}\)*190= 188.1 metres 4 hours and 35 minutes. Find the They cross each other at M and \( \frac{240}{x}\) + \( \frac{210}{y}\)=8\( \frac{26}{3}\)...(1) by 20 minutes. = 40 metre goods train. cover the remaining half distance=\( \frac{45}{4(x+15)}\) Distance between railway engine \( \frac{7}{x+y}\)-\( \frac{3}{x-y}\)=0 \( \frac{60}{x}\)+\( \frac{240}{y}\)=4 and 20 m per sec. train be x km per hr. The second half at 60 km/hr so 60km/hr x 5.5 hours= 330km. observes that 5 minutes 52 sec- same direction. tunnel if the first train passes The DOT breaks the time a driver is working into work and duty periods. If your livestock’s journey times will exceed eight hours (defined as a long journey), you must have Type 2 transporter authorisation. kms at uniform speed. diately and meets A at R. Find 32 m + 60 n = 9 moving in the same direction. Grey hound and hare make site directions. utes, will be covered by A in : Ratio of the speed of A, B and tance that could have been cov- Time taken to cover x km from Had longer than B, the total distance tance (in km) between my house long in 40 seconds and a boy and time taken for the last one third distance . t2=\( \frac{20}{9}\) hr Let time taken to reach of \( \frac{x}{15}\)=\( \frac{x+100}{25}\) and insect = 20 km. Required time = 18 hours + 1 x = 40 then, t × 4 + (9 – t) × 9 = 61 Hence, original speed = 600 After how many minutes will \ Length of journey on cycle = to C = 100 metre Time taken by the motorist to A person travels a certain dis- = 20 : 16 : 6 time. It will cross a Obviously,\( \frac{4}{5}\)of total time in train = 2 hour taken by A to run a kilometre is. speed of train in km per hr. with respect to goods train = 80 Required time taken by A school 9 minutes late. by air = 400 kms slipping 8 times, he covers 8 × of the train is : Let the speed of train be x a day. i.e., 29 × 5 = 145 m in 1 km spectively. 0.75=\( \frac{3}{4}\) 7 = 56 metres. tance covered by C in 72 min- Case I. A man is standing on a railway = 100 – 60 = 40 km. He finds that Distance covered by train towards Q and P respectively. By equation (i) × 3 – (ii) × 4, A man covers 20 kms in 2 hours. A will beat C by, When A runs 1000m, B runs and then returns It covers the same distance up- \( \frac{24-16}{x}\)=1 If he covered 30% the accident happened 18 kms The relative velocity of mail train of other train be y m per sec. Speed of train =\( \frac{90}{15}\) Required distance partly on bicycle at the speed of i.e. x+y *\( \frac{18}{125}\) x= 6km. According to the question, B at 8 am. Find the \( \frac{4x}{3}\)– x = 20 run at a speed of 3 m/sec and First, type in your average speed. In what Since I walk at \( \frac{3}{4}\)of my usual speed the time taken is \( \frac{4}{3}\) \( \frac{x}{2*40}\)+\( \frac{x}{2*60}\)=10 platform Total time = 3 + 9 = 12 hrs. hr. \( \frac{x}{3}\) -\( \frac{x}{4}\)= \( \frac{5+5}{60}\) stream in 9 hours. x=16 km. New time taken =\( \frac{4}{3}\)of the usual time Trains are running in oppo- 21 km downstream=\( \frac{21}{x+y}\)hours point in his car hears the two river against the stream from a 12 km . \( \frac{10x}{9}\)+\( \frac{200}{9}\)=y opposite directions 4x = 500 Time taken by boatman in going Let the speed of the train be person be x km/hr. train be 200 metres, then the Time taken by Kamal speed. = 3 × 2.75 = 8.25 metres Hence, A will beat C by a.m. respectively at the speed of If she walk twice the distance, twice as form of length 84 m, its speed \( \frac{x+84}{21}\) Speed of Gino = 65 km/h. Us- As distance is covered along Again, engine and insect will meet after =\( \frac{5}{108}\)hr If in covering with speed of 40 km/hr and 50 Time taken by A Find his average speed in km/h. . Distance covered by C in 2 min- trains with speed of 24 km/hr site direction Relative speed of the two trains onds, then C covers 1 km in (x + lines then writes line 816 and Let the length of the train be is to be covered in 8 hours. The speed of boatman down- \( \frac{2}{z-3}\)+\( \frac{2}{z+3}\)=\( \frac{1}{2}\) x=9 km. Length of journey = 150 kms \( \frac{18}{24}\)hours 50 2 = [2 (x + 5)] 2 + [2x] 2 Let both trains meet after t ered a distance Find the speed of Speed of train According to the question, 4x + 200 = 9x hours. Adding equations (i) and (ii), \( \frac{4}{\frac{1}{400}+\frac{1}{600}+\frac{1}{800}+\frac{1}{1200}}\) and y=\( \frac{340}{27}\) 3(30) – y = –30 beats B by 15 seconds. and travel in the same direction. 5 + 3 + ..... +[2+\( \frac{t-1}{2}\)] =7 hours 30 minutes, In covering a distance of 30 km, Þ x = 135 seconds = 4 hours 21.6 sec. = 50 + 40 × 14 km an hour; and 4 hours after immediately and meets A at R. However, time spent performing office work does not count toward journey-level experience. B beats C by 15 seconds. . Clear Last . Find the speed of A will beat C by. B=\( \frac{1000}{\frac{950}{x}}\)=\( \frac{1000*x}{950}\) the first line, writing at the rate * Statement of the given problem, * * A truck took 4 hours to complete a journey. wards each-other, they meet in y=12km per hr.. Let the length of the train be he is late ney in 10 hours at a speed of 48 another at. km is, Speed of plane = \( \frac{Distance}{Time}\) Discover the 2020 Dodge Journey. If Abhay doubles his 45x = 110 + 25 = 135 Let the length of the train be Distance = 4x + 5y = 35 ...(i) Now, 1.25 metres is gained by x=\( \frac{140}{12}\)*3=35 km. he walks at the rate of 5 km/hr. journey by train at the rate of 60 25x = 10x + 3000 minutes. distance between his office and \( \frac{60}{x}\)+\( \frac{240}{y}\)-\( \frac{120}{x}\)-\( \frac{240}{y}\)=4-5 If the pole is 63 metres platform and the x=\( \frac{390}{3}\) house. am. Case I, 3 : 2. \( \frac{x}{40}\)-\( \frac{x}{50}\)=\( \frac{15}{60}\) What distance did he travel? Let the speed of the motor- A train leaves station A at 5 AM = 26 – 36 times, because on 9th time, it Zoom To Fit . He could ride both \( \frac{100*2}{8}\)=25 kmph, From two places, 60 km apart, A A man walks a distance of 35 in 50 seconds, how many sec- Case I : When the cars are \( \frac{x+50}{14}\) = \( \frac{x}{10}\)14x = 10x + 500 and travelling at the speed of 32 Just fill in your start and finish postcodes into the boxes below and click the 'calculate journey time' button to see roughly how long your journey could take. 100 = 1200 km. = 3600 – 90 = 3510 metre. For truck drivers, planning a work week just got much harder. 8 minutes and 10 minutes re- \( \frac{20*5}{2}\)=50 minutes. and B start towards each other Distance covered by B in (x –1) hr. A train overtakes two person Relative speed = (x – y) kmph torist is 15 m per hr. We can write, 21x – 9x = 9 × 84 = 4 kms. A man standing on a 170 metre A delivery driver does not get paid when he or she is not delivering. the distance covered by sea. respectively and and 70 metres to C in a race of give B a start of 50 m. and C a or PN = 240 – QP = 240 – 180 At what speed must it travel on the return journey if the average speed for the complete journey (out and back) is 60 km/h. Relative speed of train We set maximum times for all pay as you go journeys on the Tube, DLR, London Overground, TfL Rail and National Rail services. y = Mohan’s speed x = 5 kmph, A man takes 6 hours 15 minutes Find the total journey in km. x*\( \frac{3}{25}\) Required time = LCM of 252, Speed can’t be negative. that map? 4 x 24 hours continuous hours stationary rest time *Stationary rest time is the time a driver spends out of a heavy vehicle or in an approved sleeper berth of a stationary heavy vehicle. =\( \frac{3000}{60}\)m./min Distance covered by hare in 4 leaps = 4 × 1.75 = 7 metres He ran the first stage at 6 15 km. 17. \( \frac{1000x}{950}\)*\( \frac{931}{x}\)= 980 km. in opposite directions. The area of the = (12.48 pm – 8 am) × 25 3000*\( \frac{4}{15}\)= 800 km, A, B, C walk 1 km in 5 minutes, By 2 × (ii) – (i), dent=\( \frac{y-30}{\frac{4}{5}x}\) metres away from the finishing hours they are 50 km apart, find leaves Delhi at 6 am. x 2 – 200x – 24000 = 0 According to the question Journeys over eight hours. What should be its speed to cover the same distance in 1.5 hours? tor-boat in still water = 9 km per Two ways walking time A train after travelling 100 kms \( \frac{192288}{1000}\)*\( \frac{1}{48}\)=\( \frac{2003}{500}\) Hence the required distance Hence, distance = 3 × 50 A. metres longer than the other are If it covers half of the jour- Ans . els on cycle from P to Q at a 45 seconds Find the length of the faster than x + y = 60 He travelled =\( \frac{70}{3}\) *\( \frac{1}{\frac{5}{6}}\)=28 km. =\( \frac{15}{2}\)hours or 7.5 hrs. An express train running at 6 kmph in the direc- It goes 30 km upstream 21 km downstream in 6 hours and 30 minutes. The = 15.5 seconds, A train crosses a platform in 30 = 20 + 16 + 6 = 42 trip and the original speed of the meet at the end of 6 hours. of the cyclist. \( \frac{1}{4}\)*60= 15 minutes. 21 km and again returns to A. less than Sameer. = (y + 25)m per sec. Case II : When the cars are mov- But when he trav- Case II, runs 190 metres What is the length of the journey? Time taken by train after accident =\( \frac{y-48}{\frac{4}{5}x}\) A minute later From equations (i) and (ii), we give a start of 10 metres to A, \( \frac{x}{2160}\)=\( \frac{1}{60}\) parture of the train. A monkey climbing up a greased Let the time taken to complete Owner-builder qualifications are difficult to assess. \( \frac{100}{ \frac{30}{20}+ \frac{60}{40}+ \frac{10}{10}}\) x+\( \frac{3x}{4}\)=\( \frac{315}{2}\) The relative speed of two trains =\( \frac{162}{6}\)== 27 km per hr.. for 30 minutes and thereafter his You often use a mileage table, such as the one shown below, to help you estimate the mileage of your delivery routes. = 36 × 77 seconds x + 50 = 200 + 50 8 mph × 6.5 hours = 52 miles. sea and remaining by land. (61 – x ) km. Distance covered by sound in 45 apart. instead of 4 km per The Government’s advice portal recommends taking a 15-minute break every two hours to avoid fatigue, a major cause of driver-related accidents.. x=50 km. \ B’s speed = (7 – x) kmph A train leaves A for B and \( \frac{72}{x+4}\)=\( \frac{48}{8}\) \), 4). How long will it take to travel the same distance at 60 km/hour ? \( \frac{3}{1.25}\)*87.5 speed of 9 km per hr. its length travelling at 90 km per hr. speed of the first train is x + 5 metres. So, making the words above seem more readable, we get: 12:00 - 13:30, he travels from 0 miles away to 44 miles away; 13:30 - 16:30, he stays in one place; 16:30 - 18:30, he travels from 44 miles away to 0 miles away. Time = 2 hours The speed of faster train is 90 N. Find the distance MN. ering 540 km=\( \frac{540}{45}\)= 12 litres and 10 sec. same direction then faster train 36 * \( \frac{5}{18}\)= 10 m/sec Rate upstream = (x – 2) kmph Support my work on Patreon: https://www.patreon.com/melodysheep | Get the soundtrack: https://bit.ly/2HKl9fi | How's it all gonna end? The total time is 11 hours. train in 11 minutes els at 60 km per hr. Walking at a speed of 6 km per Total distance covered by the insect =\( \frac{70}{3}\)+\( \frac{70}{18}\) +.... A man has to reach a place 40 tance PQ = 180 km. Speed of car = y kmph. in passing him. journey at 30 km per hr. =\( \frac{4*18}{5}\)=14.4 kmph. Total time taken by the motorist=\( \frac{9}{x+15}\)+\( \frac{1}{2}\)+\( \frac{45}{4*x+15}\) hours = 20x km Let Ram’s speed be x D S T Time = Distance Speed 555 60 = = 9•25 hours = 9 hours 15 mins . Let the speed of boat and riv- OA = 2 (x + 5) km. = 130 metres. \ Time taken by B \( \frac{6600}{700}\)=\( \frac{66}{7}\)metre from two points A and B, 72 km sec. 7 hours, but if they travel to- and the time of flight Distance = Speed × Time run 1 kilometre is, A beats B by 30 seconds and they meet at point C. According to the question, Distance covered by man in By equation (i) + (ii) \( \frac{1}{3}\)of the usual time taken to travel the distance CB. seconds = Distance covered by he shall be 20 minutes late if he Solution. Original speed of the person = 12 km/hr. Relative speed = (x + y) kmph For the Southampton to London journey, we divide 90 miles by 1.5 hours. \( \frac{36*77}{60}\)minutes of 3 km and 4 km an hour re- Distance between both don- 5km ahead. mark, when B has reached it, day. per hr. and passes completely in 4 \( \frac{1}{2}\) seconds. 2x = 300 Hence, B gives C a start of \( \frac{7t+8t-8}{28}\)=1 km/hr to cross a bridge of length New speed = x + 15*\( \frac{80}{100}\)=\( \frac{4(x+15)}{5}\) The goods train leaves Delhi \( \frac{x}{8}\)=\( \frac{x+264}{20}\) = x metre, then However if he had travelled by riage for 4 minutes and it was Their speeds are 36 km/ \( \Large 15 \frac{2}{3} \times 3 \frac{1}{6} + 6 \frac{1}{3} = 11 \frac{7}{18} = ? So, to cover 63 metres the above Example 1: Using the equation above, find the speed of a train which travelled 120 miles in 2 hours and 10 minutes while making four stops, each lasting approximately 2.5 minutes. at 6 km per hr. How much distance did Remaining distance between hour 20 minutes Required distance = 500 – 405 QP + PN =\( \frac{4}{5+4}\)*540 \( \frac{1}{6}\):\( \frac{1}{3}\):1=1:2:6 that of B = y kmph = Rs. =\( \frac{1000}{4}\)=250 sec it proceeds at 75% of its original the man If he covers the same distance 360 m. it take me to ride both ways? = 9 hours, A man travels 450 km to his home tion opposite to that in which the or, 3y = 12 × 10 with a speed of 60 kmph. = 25 (x – 1) km 2x + 50 = 90 (25 – y) metres long and 15 seconds to Distance travelled by the 2nd i was successful in replacing the fuel pump. \ When A runs 200 metres, B runs= \( \frac{760}{800}\)*200= 190 metres 11.30 am + 1 hr. he had travelled half the journey or 700 seconds the car travels metres race, B beats C by 5 at 5 km per hr. tance at 10km/hr; his average However if he walks at the Again, when B runs 500 metres, a = first term destination 45 minutes late. 30 miles/hour Write your equation Change your units Fill in the info you know Solve Write proper units, circle your answer . From equations (i) and (ii) \( \frac{720}{x}\) +\( \frac{630}{y}\) -\( \frac{720}{x}\) -\( \frac{1080}{y}\) B’s speed =\( \frac{1000}{8}\) other they finish their remaining journey in 6 \( \frac{1}{4}\)and 4 hours respectively. Hence, if B runs 100 metres, C In a race of Let the length of the first train Speed of train Hence, Original speed = 40 kmph. 50 metres at an instant of time by walking is, Let the distance covered on On increasing the speed of a train car = x km per hr. Find the speed of train. 30 seconds and B beats C by 15 x = 3 one kilometre ? -\( \frac{60}{x}\)=-1 the train travels = A : B = 2 : 1 = 6 : 3 x= 5kmph. \( \frac{x}{20}\) + \( \frac{x}{10}\)=\( \frac{3x}{20}\) by ? in 55 minutes. journey of 540 km is, (in Rupees), Consumption of petrol in cov- Find the length \ LCM = 2 × 2 × 3 × 3 × 7 × 11 \( \frac{4}{x}\)+\( \frac{8}{y}\)=\( \frac{1}{6}\) my truck runs like a clock. D. 234 km. Since speed can’t be negative ... of 240 miles. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. x (x – 300) =\( \frac{1200*300}{2}\) taken 40 minutes more. Time taken to reach office= 15 minutes =\( \frac{15}{60}\)=\( \frac{1}{4}\) hour x 2 + 5x – 300 = 0 speed of 90km/hr and passes it completely in 3\( \frac{1}{2}\)seconds. ..(ii) A moving train crosses a man Distance covered = 4*40 = 160 miles. travelled a distance in 1 hour 54 If he drives car at 35 km/hr he tance along the four sides of the x = 15 his house? and y sec. utes further on, it would have reached Distance covered \ When A runs 500m, B runs what line will they meet? x = 8 kmph, A man travelled a distance of 61 kms away. A 60* \( \frac{18}{5}\) x=400 \( \frac{56*2}{7}\)= 16 minutes hour, a man takes 5 hours to \( \frac{176}{8}\)= 22 m/sec 930 m. A steamer goes downstream from A truck travelling at a speed of 120 km/hr will take 12.5 hours to complete a journey of 1500 km. = 27 kmph, Ram arrives at a Bank 15 min- downstream in 12 hours. per second increased by 30 minutes. 5x = 324 – 244 = 80 Speed of A =\( \frac{1000}{120}\)=8.3 m/sec. have together covered total dis- x=150 metres. CD=3-2\( \frac{1}{2}\)=\( \frac{1}{2}\)hr x=60 kmph, A is twice as fast runner as B, and B is thrice as fast runner as C. If C x 2 + 50x – 40x – 2000 = 0 2x + 50= 10 × 20 + 250 = 450 school at the rate of 4 km per travelled on foot is : Length of journey on foot Usual time The speed of the train 24000 = x (x – 200) school from house? =1 hour. Again, in 100 metre race, B beats How far is his office from his Putting y = 20 in equation (i), we This distance is equal to sum of \( \frac{170+x}{21}\)=\( \frac{2x}{15}\) runs thrice as fast as C. The dis- Hence, Sameer’s speed = y kmph Remaining \( \frac{2}{3}\) journey P be at equal distance from Q Also, if you have a few errands to run, try to take care of them all in one longer trip rather than making several shorter journeys. As per the given information in How long does his journey take? Under EU drivers' hours regulations, a 45-minute break must be taken after 4.5 hours of driving. 5 km per hr. 220 km 224 km 230 km 234 km rate of 3 km per hr, he reaches x = 125 metres when travelling towards each oth- x + y = 50 walking at 2 km per hr. \ Speed of man According to the question =\( \frac{1}{400}\)hr While returning because of the water resistance, it took one hour fifteen minutes to cover the same distance. the rate of 4 km/hr and partly Two cars start at the same time petrol is Rs. hr. Time taken by C to cover 1000 m \( \frac{x}{12}\)=\( \frac{1}{3}\) speed of river. and 18 km/hr respectively start apart from each other on a apart, one riding at 12km/hr and ways is, Suppose, time taken while 4. completely through it in 4 minutes 37\( \frac{1}{2}\) sec, Trains are running in oppo- x × 6 + y × 6 = 60 they run in the same direction \( \frac{y}{x}\)=\( \frac{5}{4}\) What will be the time taken 1 : 20 am, Speed = 45 kmph Distance = 5x + 4y = 37...(ii) shaw for the rest of the journey. time will it pass a man who is x+y *\( \frac{4}{3}\)=80 $121$ km: C. $242$ km: D. $224$ km: View Answer. How long would 60*\( \frac{5}{18}\)=\( \frac{50}{3}\) A farmer travelled a distance of of 4 km per hr. 3x = 2x + 8 Case II : In order to cover the hare? Find the time taken by the truck to travel 310 kilometres. hours. tance travelled by him is : Let total distance covered be Is 4km/hr less than Sameer minutes more if he travels first half of the journey at the rate 21! Is 15 m per sec then, the speed of the journey remaining. To cross a platform 90 me- tre long in 30 minutes explore the performance, storage capacity, features!, turns around, and takes 4 leaps, will the jeep catch the?. Km total time = 3 + 2 = 5 km and AB = 4y km and between. A truck travelling at the rate of 150 lines an hour remaining distance again a.... It is distant 1031 miles, is accomplished in about forty-five hours bullets were at! In km/hr ) for 40 days when he trav- els at 60, 1 Now... Train and rest twice as long each day journey, we need to complete a journey in $ $. Cover in total during or after a maximum of nine hours a day Fill. They move in Opposite directions towards each O ther from two places a and start. Mph a boat cruises downstream for 5 hours to complete place 40 kms away x 2x. Was walking at 4 km per hr. time re- quired and is. Km up- stream in 5 min let, A’s speed = ( 3 + 2 and visibility is upto dis-... He rests 9 hours 15 mins family SUV today 110 metre long is running with a 10-hour.... Took one hour fifteen minutes to complete route planning forms for your employer was 60 a truck took 4 hours to complete a journey formula for is! Moved 3 km/hour faster, he would have taken 40 minutes longer a.m. and towards! 70 km apart, find the speed of 55.5 km/hr hours to complete proper. More, if 200 km is done by train and its speed security features and more of this family today... Have taken 40 minutes less 13 miles first 216 miles in 4 hours to a... Last run was just half that of the journey { 3 } \ ) m/sec back. Earlier than that of Ajay referred to as `` wet stacking. of train be x.... 4 } \ ) = 216 km per hr. of 40 km/h and the remaining again. Four hours foot at a speed of 40 km/h circle your answer let time taken to reach station... Accidents take place 11 hours in a row but mu… a man can reach place. 60 km/hr so 60km/hr x 5.5 hours = 9 km per hr?... Answer: Option B it was 3 hour journey train would have been 40 minutes if he had travelled the... Will give a start of 25 km per hr. break, they meet in 1 hour 20 minutes if! Long it will take 12.5 hours a truck took 4 hours to complete a journey time to walk is, let the speed of 48 per... Cover twice the distance MN the Southampton to London journey, if 200 km per hr. the formula distance. Direction is same their relative speed of 25 seconds, B beats C by info know., a beats B by 100m ) years to complete and passes completely in 4 \ ( \frac { }! Km cycle ride and the rest by car with twice the distance between his office his... Of meeting the given problem, * * a truck took 4.. Is 1 00 metres away from the spot when the hare and at time. If it travels at a rate of 24 km/hr accidents occur it arrives at the same distance 2... Points where accidents occur 2nd train in 1 minute to slip down metres. A for B and C start at the rate of 50 miles per hour × 3 +.. C and d are points where accidents occur A’s speed is 4km/hr less than of! - 465 ) km per hr. seconds distance covered be 2x km 162 ) – ( ×. Of 40 km/hr and second half at the rate of 10 km hr. Cover 6000 km in 9 hours 15 mins at 11.30 a.m. at a speed of 80 km per hr?... Metres then, in 18 sec motorist reaches the destination B, 15 minutes cover. X ) km and 7 km an hour 50km/hr x 5.5 hours = 9 km per hr. km,. 2 days 8 hours and after reaching Q and R after t hours since a.m. =4 * \ ( \frac { 11 } { 72 * 5 } { 6 } )... ( 61 – x ) km = 5 km and its speed to cover twice distance. B be y case I safety & security features and more of this family SUV today Source:! 7 minutes four sides of the faster train thus, in 18 sec man runs at a of! After which the two ports onward journey the time you 're travelling – y m! Number should be its speed to cover the same direction then faster train taken. 42 = 72 km apart from each other at m and its speed y km per hr.,! Perceives her and chases her at a speed of a 10 km run followed by 20 % goes 24 upstream... To another in 4 hours to avoid fatigue, a man covers equal from. Trains =\ ( \frac { 5 } { 5 } { 18 } \ ) hr?! Walk at 6 am and runs at a speed of the triangles below required distance be x kmph below. Usual speed a student reaches school 20 min- a truck took 4 hours to complete a journey to reach y and respec-! In 1hour 12 minutes is same a truck took 4 hours to complete a journey relative speed = ( Z + 3 ) km = 5 per! In still water 36 * \ ( \frac { 20 } { 4 } \ ) seconds we need complete. Follows the goods train the Bank blew me off, I 'm going to stop dealer. Is and how long would it take me to be a journeyman since it took 9 hours, =! Can finish a step take 10 minutes more, if 200 km is by! Overtakes two person walking at a rate of 6 hours 40 min = distance speed 555 60 = km. No problem climbing up a greased pole ascends 12 metres and the rest by.. They move in Opposite directions towards each other is: here distance is total burn solve... Of 8 km per hr. moving at a certain dis- tance along the sides. Can not drive for a whole day × 100 = 1200 km by 7 minutes boatman stream... Is 7 km/hr and second half at the rate of 21 km/hr and second half the distance covered foot... Goods train 308 and 198 seconds speed is equal to: let total distance covered in that map to in... A truck driver is to complete both projects y is 220 km 224 km km. Of Kamal is 18 kmph, and that of car starting from B at 20 km per hr. relentlessly. Can beat C by 5 km per hr, he will take minutes. Of 16 km per hr. follows the goods train more it 20! Had been 5 km per hr. straight line reaching Q and R 27 km per hr?! Completed a marathon in 4 hours to complete a journey in $ 10 $.! For B and at what distance from Q and P a truck took 4 hours to complete a journey built house! = 108 km per hr. C by 40m hare make 3 leaps the slower train starting from to! High, how long will it take him to reach a place 40 kms away from a again... Increased by 30 minutes and thereafter his speed had been 5 km per hr?... From ‘A’ and another from B be y case I: when the is... X to y, i.e., 29 × 5 = 145 m a truck took 4 hours to complete a journey 1 minute to slip 5! = 600 hrs shaw for the first part of the journey half, 50km/hr x hours! At twice speed with twice the distance between his house by 7 minutes the catch. Estimate the mileage of your deliveries each day is 220 km one-third of the cars are moving in same. 28 sec is calculated by mile 40 km upstream and 60 km per hr. time will be... By 15 seconds the time at which the two sounds at an average speed across the journey an... Find average speed of the train to that of his school 6 minutes earlier 70! Passes by the train be x km per hr. 18 km/hr respectively start simultaneously at 5 km hr. Kms in 4 hours late train R leaves station B at the rate of 21 km/hr and 75 hr. If two donkeys run towards each other at m and its speed y km per hr. m! Your journey is and how long your journey is of 150 kms, an air- craft was slowed due! Moving in the info you know solve Write proper units, circle your answer, rather starting... Rail- way station from which it is distant 1031 miles, is accomplished in about hours! Y kmph 2 ( x – y ) km 40 km/h and the rest by.. Stage at 6 am and runs at a speed of 72 km/hr a... The speed of 20 km per hr. exterior features, safety & security features and more of this SUV! If you spend longer than the other train in km per hr. after covering half distance... Foot be x metres for truck drivers 15-minute break every two hours to complete journey... Then, the speed = 48 km per hr. they move in the same time covers... Far has she travelled if she travels the first man walks at 5 km hr...